Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 5 (Q.No. 40)
40.
In an area of 200 hectare, water table drops by 4 m. If the porosity is 0.35 and the specific retention is 0.15, change in volume of storage in the aquifer is
Discussion:
9 comments Page 1 of 1.
Vinod Kumar said:
1 decade ago
Can you explain, please?
Jagan said:
9 years ago
Please Explain it.
Sadashiva said:
9 years ago
Porosity = specific yield + specific retention.
0.35 = 0.15 + specific retention.
Specific retention = 0.25.
Change in volume = 0.25 * 200 * 4m.
1.6 * 10^6 m.
0.35 = 0.15 + specific retention.
Specific retention = 0.25.
Change in volume = 0.25 * 200 * 4m.
1.6 * 10^6 m.
Reshma said:
7 years ago
Specific retention is 0.25, is given in question, did you mean specific yield?
Reshma said:
7 years ago
Also .25x200x4 is 200.
How you get 1.6x106? @Sadasiva.
How you get 1.6x106? @Sadasiva.
Phani said:
7 years ago
Here = 0.20 * 4 * 200 * 10^4.
=1.6 x 10^6 m.
=1.6 x 10^6 m.
Sadashiva said:
7 years ago
Yes, agree @Reshma.
Sadashiva said:
7 years ago
Porosity = specific yield + specific retention.
0.35 = specific yield + 0.15,
Specific yield = 0.20,
Change in volume = 0.2 * 200hectare * 4m*10000 (1 Hectare=10000sq.mt) S.
1.6 * 10^6 m.
0.35 = specific yield + 0.15,
Specific yield = 0.20,
Change in volume = 0.2 * 200hectare * 4m*10000 (1 Hectare=10000sq.mt) S.
1.6 * 10^6 m.
Jitendra khosla said:
4 years ago
Please explain me the given answer.
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