Discussion :: GATE Exam Questions - Section 3 (Q.No.17)
|Divya said: (Sep 28, 2015)|
|Sudeep said: (Nov 16, 2015)|
|Correct answer is 3/4.
C = 0; D = 0.
Therefore, (qf)cir/(qf)sq = 0.3yBNq/0.4yBNq.
|Shubham said: (Jul 16, 2016)|
|Yeah. The Correct answer is 3/4.|
|Priyanka said: (Mar 25, 2017)|
|The correct answer is A.|
|Swastik said: (Sep 4, 2017)|
|Correct answer is A.|
|Roy said: (Nov 26, 2017)|
|Ietakshay said: (Jul 31, 2018)|
|Given Ans 1.3 is correct.
Ratio = strength of circular section / Strength of Square section.
If We assumed Side or Dia. Is 4 cm.
And Load P is the same,
Then Ratio of ultimate stresses of circular to the square is;
= (P/12.56) / (P/16).
= P .16/P. 12.56.
|Mohd Tariq said: (Jan 4, 2019)|
|The Correct answer is 3/4.|
|Jaydev Kumar Saha said: (Jan 9, 2019)|
|Yes, agree the Correct answer is A.|
|Bhutan said: (Jun 8, 2019)|
|Option A, 3/4 is correct.|
|Bhutan said: (Jun 19, 2019)|
|The Correct option is A.|
|Purushottam said: (Feb 5, 2020)|
|Correct option B & D.
4/3 = 1.3.
|Rand said: (Aug 21, 2020)|
|What if its cohesion soil? any difference? Explain me.|
|Narayan Saha said: (Dec 6, 2020)|
|The Correct answer will be option A.|
|Santosh said: (Dec 24, 2020)|
|3/4 is the right answer.|
|Mahesh Sin said: (Sep 30, 2021)|
|Area of circular footing = π/4 d2.
= 0.785 d2.
Area of square = d2(because d=l).
Bearing capacity = load/area.
Circular = load/0.785d2.
Square. = load/d2.
Ratio = load/0.785d2*d2/load.
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