Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 6 (Q.No. 31)
31.
A borrow pit soil has a dry density of 17 kN/m3. How many cubic meters of this soil will be required to construct an embankment of 100 m3 volume with a dry density of 16 kN/m3.
Discussion:
7 comments Page 1 of 1.
Vaish said:
7 years ago
It should be 106.25 m3.
(1)
Mohan said:
10 years ago
How to solve this question? Kindly give explanation.
Navneet said:
10 years ago
(16*100)/17 = 94.12.
Fazil said:
7 years ago
Thank you so much @Navneet.
Manish said:
7 years ago
How?
Could you please give the full solution clearly?
Could you please give the full solution clearly?
Sweetie said:
5 years ago
V1/V2 = yd2/yd1.
V1/100 = 16/17.
V1 = 94.11m^3.
V1/100 = 16/17.
V1 = 94.11m^3.
Heramb said:
5 years ago
@All.
Please listen, Here, I solved in detail.
A] Dry density is given;
I) Borrow pit dry density =17Kn/m3
II) Embankment dry density =16Kn/m3
B] To find out weight of soil
I) Borrow pit
W=Dry density X volume
W= 17 X 1
W= 17KN/m3 ..[Takevolume=1.standardcase]
II) Embankment
W=Dry density X volume.
W= 16 X 1.
W=16KN/m3..[Take Volume=1.standard case]
C]. To find out the volume for 1 m3.
VOLUME OF borrow pit= Weight of soil of Embankment /Dry density of borrow pit
VOLUME OF borrow pit= 16/17
=0.94012 m3.
Therefore,
1 m3 of Embankment =0.94012 m3 of Borrow Pit.
100 m3 of Embankment =[ x] m3 of Borrow Pit.
x *1 = 100 * 0.94012,
x =94.012%.
Therefore, volume is 94.012% of Borrow Pit.
Please listen, Here, I solved in detail.
A] Dry density is given;
I) Borrow pit dry density =17Kn/m3
II) Embankment dry density =16Kn/m3
B] To find out weight of soil
I) Borrow pit
W=Dry density X volume
W= 17 X 1
W= 17KN/m3 ..[Takevolume=1.standardcase]
II) Embankment
W=Dry density X volume.
W= 16 X 1.
W=16KN/m3..[Take Volume=1.standard case]
C]. To find out the volume for 1 m3.
VOLUME OF borrow pit= Weight of soil of Embankment /Dry density of borrow pit
VOLUME OF borrow pit= 16/17
=0.94012 m3.
Therefore,
1 m3 of Embankment =0.94012 m3 of Borrow Pit.
100 m3 of Embankment =[ x] m3 of Borrow Pit.
x *1 = 100 * 0.94012,
x =94.012%.
Therefore, volume is 94.012% of Borrow Pit.
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