# Civil Engineering - GATE Exam Questions - Discussion

### Discussion :: GATE Exam Questions - Section 6 (Q.No.31)

31.

A borrow pit soil has a dry density of 17 kN/m3. How many cubic meters of this soil will be required to construct an embankment of 100 m3 volume with a dry density of 16 kN/m3.

 [A]. 94 m3 [B]. 106 m3 [C]. 100 m3 [D]. 90 m3

Explanation:

No answer description available for this question.

 Mohan said: (Sep 4, 2015) How to solve this question? Kindly give explanation.

 Navneet said: (Nov 15, 2015) (16*100)/17 = 94.12.

 Fazil said: (May 9, 2018) Thank you so much @Navneet.

 Manish said: (Aug 6, 2018) How? Could you please give the full solution clearly?

 Vaish said: (Feb 23, 2019) It should be 106.25 m3.

 Sweetie said: (Oct 11, 2020) V1/V2 = yd2/yd1. V1/100 = 16/17. V1 = 94.11m^3.

 Heramb said: (Oct 24, 2020) @All. Please listen, Here, I solved in detail. A] Dry density is given; I) Borrow pit dry density =17Kn/m3 II) Embankment dry density =16Kn/m3 B] To find out weight of soil I) Borrow pit W=Dry density X volume W= 17 X 1 W= 17KN/m3 ..[Takevolume=1.standardcase] II) Embankment W=Dry density X volume. W= 16 X 1. W=16KN/m3..[Take Volume=1.standard case] C]. To find out the volume for 1 m3. VOLUME OF borrow pit= Weight of soil of Embankment /Dry density of borrow pit VOLUME OF borrow pit= 16/17 =0.94012 m3. Therefore, 1 m3 of Embankment =0.94012 m3 of Borrow Pit. 100 m3 of Embankment =[ x] m3 of Borrow Pit. x *1 = 100 * 0.94012, x =94.012%. Therefore, volume is 94.012% of Borrow Pit.