Civil Engineering - GATE Exam Questions - Discussion

31. 

A borrow pit soil has a dry density of 17 kN/m3. How many cubic meters of this soil will be required to construct an embankment of 100 m3 volume with a dry density of 16 kN/m3.

[A]. 94 m3
[B]. 106 m3
[C]. 100 m3
[D]. 90 m3

Answer: Option A

Explanation:

No answer description available for this question.

Mohan said: (Sep 4, 2015)  
How to solve this question? Kindly give explanation.

Navneet said: (Nov 15, 2015)  
(16*100)/17 = 94.12.

Fazil said: (May 9, 2018)  
Thank you so much @Navneet.

Manish said: (Aug 6, 2018)  
How?

Could you please give the full solution clearly?

Vaish said: (Feb 23, 2019)  
It should be 106.25 m3.

Sweetie said: (Oct 11, 2020)  
V1/V2 = yd2/yd1.
V1/100 = 16/17.
V1 = 94.11m^3.

Heramb said: (Oct 24, 2020)  
@All.

Please listen, Here, I solved in detail.

A] Dry density is given;

I) Borrow pit dry density =17Kn/m3
II) Embankment dry density =16Kn/m3

B] To find out weight of soil
I) Borrow pit
W=Dry density X volume
W= 17 X 1
W= 17KN/m3 ..[Takevolume=1.standardcase]

II) Embankment
W=Dry density X volume.
W= 16 X 1.
W=16KN/m3..[Take Volume=1.standard case]

C]. To find out the volume for 1 m3.

VOLUME OF borrow pit= Weight of soil of Embankment /Dry density of borrow pit
VOLUME OF borrow pit= 16/17
=0.94012 m3.

Therefore,
1 m3 of Embankment =0.94012 m3 of Borrow Pit.
100 m3 of Embankment =[ x] m3 of Borrow Pit.
x *1 = 100 * 0.94012,
x =94.012%.

Therefore, volume is 94.012% of Borrow Pit.

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