Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 2 (Q.No. 8)
8.
The number of revolutions of a current meter in 50 seconds were found to be 12 and 30 corresponding to the velocities of 0.25 and 0.46 m/s respectively. What velocity (in m/s) would be indicated by 50 revolutions of that current meter in one minute ?
Discussion:
11 comments Page 1 of 2.
Chris said:
10 years ago
Please give me a formula for this?
Giri said:
10 years ago
h + nm/7854512.
Harshitha said:
9 years ago
Please give me the formula and explanation.
Pradeep said:
9 years ago
I think the answer is 0.42.
Rakesh kumar said:
9 years ago
Can anyone please explain this properly with the formula?
Mekdi said:
9 years ago
Please explain it clearly.
Sanketh said:
8 years ago
The formula for current meter is v=aN+b where a, b are current meter constants and N is no of revolutions made by the current meter.
Use this formula & calculate the constants a, b and find the velocity for 50 revolutions.
Use this formula & calculate the constants a, b and find the velocity for 50 revolutions.
Yogesh said:
8 years ago
Here, v = aN + b.
Where N is no of revolution in sec.
Where N is no of revolution in sec.
Noman said:
5 years ago
@Yogesh.
Then, how to find a&b?
Then, how to find a&b?
Momin said:
5 years ago
0.25 = a12+b
0.46 = a30+b find a, b
a=0.012, b=0.10
Now N =50 , v=?
V = 0.012 * 50 + 0.10,
V = 0.70.
0.46 = a30+b find a, b
a=0.012, b=0.10
Now N =50 , v=?
V = 0.012 * 50 + 0.10,
V = 0.70.
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