Civil Engineering - GATE Exam Questions - Discussion

Discussion Forum : GATE Exam Questions - Section 2 (Q.No. 8)
8.
The number of revolutions of a current meter in 50 seconds were found to be 12 and 30 corresponding to the velocities of 0.25 and 0.46 m/s respectively. What velocity (in m/s) would be indicated by 50 revolutions of that current meter in one minute ?
0.42
0.50
0.60
0.73
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

THULASIDASAN said:   5 years ago
0.25 = 12a + b.
0.46 = 30a + b.
a = 0.01167, b = 0.11
For 50s, N = 50 * 50/60 = 41.67,
So,V = (0.01167 * 41.67) + 0.11.
V = 0.6.

Momin said:   5 years ago
0.25 = a12+b
0.46 = a30+b find a, b
a=0.012, b=0.10

Now N =50 , v=?
V = 0.012 * 50 + 0.10,
V = 0.70.

Noman said:   5 years ago
@Yogesh.

Then, how to find a&b?

Yogesh said:   8 years ago
Here, v = aN + b.

Where N is no of revolution in sec.

Sanketh said:   8 years ago
The formula for current meter is v=aN+b where a, b are current meter constants and N is no of revolutions made by the current meter.

Use this formula & calculate the constants a, b and find the velocity for 50 revolutions.

Mekdi said:   8 years ago
Please explain it clearly.

Rakesh kumar said:   8 years ago
Can anyone please explain this properly with the formula?

Pradeep said:   8 years ago
I think the answer is 0.42.

Harshitha said:   9 years ago
Please give me the formula and explanation.

Giri said:   9 years ago
h + nm/7854512.


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