Civil Engineering - GATE Exam Questions - Discussion

12. 

A direct runoff hydrograph due to an isolated storm with an effective rainfall of 2 cm was trapezoidal in shape as shown in the below figure. The hydrograph corresponds to a catchment area (in sq. km) of

[A]. 790.2
[B]. 599.4
[C]. 689.5
[D]. 435.3

Answer: Option B

Explanation:

No answer description available for this question.

Pulkit said: (Dec 16, 2016)  
AREA = 90 * 1/2 * (70 + 4) * 60 * 60 * 10^(-6).

60 * 60 to convert hr to secs, 10^(-6) for sqm to sq km.

Rakesh Kumar said: (Jan 30, 2017)  
Can anyone explain even more clearly?

Akhil said: (Jun 25, 2017)  
Area =1/2 * sum of parallel side *height.

= 1/2*(70+4) * 900 *60*60*(10)^(-6),
60*60 is conversion hour to secs 10^(-6) sqm to sqkm.

Sarvesh said: (Feb 14, 2018)  
1/2*(70+4)*900*60*60*(10)^(-6) = 199.88 * 5 = 599.4.

Reshma said: (Apr 15, 2018)  
Why 900, is it 90 cumecs right?

Keshav Kaushik said: (Jan 9, 2019)  
How come 900 and why 5 has been used?

Yesika said: (Jun 21, 2019)  
Area of given DRH = volume of direct run off.

[(1/2)(70+4) * (60)*(60) * (90) ] m3=11988000 m3,
Effective rainfall = 2 cm,
Catchment area = Volume of DRH/Effective rainfall.
11988000 / (2 * 10-2) m2 = 599.4 m2.

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