Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 3 (Q.No. 13)
13.
A cantilever beam is shown in the below figure. The moment to be applied at free end for zero vertical deflection at that point is
Discussion:
15 comments Page 1 of 2.
Arjun said:
1 decade ago
I think it is 9KN*2M = 18 KN-M, as moment is defined as force X displacement.
RAKESH KUMAR said:
9 years ago
Agree @Arjun.
It is -18KN-M.
It is -18KN-M.
Rajat said:
9 years ago
12 is correct but the direction is clockwise.
Anubhav said:
8 years ago
How 12 is correct?
Xmgo said:
8 years ago
Deflection due to clockwise moment M,D1=ML^2/2EI=M*2^2/2EI.
Deflection due to point load 9kN,D2=PL^3/3EI = 9*2^3/3EI.
Since deflection has to be 0 hence D1-D2=0, M will come 12kNm clockwise.
Deflection due to point load 9kN,D2=PL^3/3EI = 9*2^3/3EI.
Since deflection has to be 0 hence D1-D2=0, M will come 12kNm clockwise.
Chhaya said:
8 years ago
Thanks @Xmgo.
Vinay singh said:
8 years ago
ML2/2EI=PL3/3EI.
Answer is 12.
Answer is 12.
TKd said:
8 years ago
Yes, the direction will be clockwise 12C.
Anand Mishra said:
7 years ago
Thanks for the explanation @xmgo.
Keshav Kaushik said:
7 years ago
WL^3/3EI - ML^2/2EI = 0.
For the above stated condition;
M comes out to be 12knm.
And it must be applied anti-clockwise as per sign convention.
For the above stated condition;
M comes out to be 12knm.
And it must be applied anti-clockwise as per sign convention.
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