Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 3 (Q.No. 10)
10.
A propped cantilever beam in shown in the below figure. The plastic moment capacity of the beam is M0. The collapse load P is
Discussion:
4 comments Page 1 of 1.
ANBu said:
1 decade ago
Let me explain please.
Nj-uniq said:
10 years ago
There are two plastic hinges formed. One at the fixed support and another below the load.
Hence internal work done = Mo*(2*theta + theta) = 3Mo*theta.
External work done = P*delta = P*theta*(L/2).
Equating we get P = 6Mo/L.
Hence internal work done = Mo*(2*theta + theta) = 3Mo*theta.
External work done = P*delta = P*theta*(L/2).
Equating we get P = 6Mo/L.
Rakesh kumar said:
9 years ago
Can anyone explain it clearly?
Chera said:
8 years ago
q = wc÷ww (formula).
Wc=q*ww. Where wc-collapse load ,ww- working load.
I.W = E.W.
3mp * θ = p * q * L÷2 * θ
so,
q = 6 M0 ÷ L.
Wc=q*ww. Where wc-collapse load ,ww- working load.
I.W = E.W.
3mp * θ = p * q * L÷2 * θ
so,
q = 6 M0 ÷ L.
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