Civil Engineering - Estimating and Costing - Discussion
Discussion Forum : Estimating and Costing - Section 1 (Q.No. 35)
35.
The reduced levels of points, 30 metres apart along the longitudinal section of a road portion between chainages 5 and 9 are shown in the given figure. If there is a uniform up-gradient of the road 120 in 1, the chainage of the point with no filling or cutting is
Discussion:
19 comments Page 1 of 2.
Saikumar said:
1 decade ago
How it is calculated?
Prabhakar said:
1 decade ago
How it is taken?
Gance said:
10 years ago
1 in 120.
So for 30 m there is rise of 0.25 m.
R.L of formation level at 6 chain = 100+0.25 = 100.25.
Now apply the similar triangles as 1/x = 1.5/(30-X).
Where, 1 = 100.25-99.25.
x = 12.
So the answer B.
So for 30 m there is rise of 0.25 m.
R.L of formation level at 6 chain = 100+0.25 = 100.25.
Now apply the similar triangles as 1/x = 1.5/(30-X).
Where, 1 = 100.25-99.25.
x = 12.
So the answer B.
Ashik said:
9 years ago
Can you explain it? Please.
Kamruz said:
9 years ago
I think it is A.
Asmaul Husna said:
8 years ago
@Gance.
Where is 1.5 from?
Where is 1.5 from?
Karthick said:
8 years ago
6+ 12 chain how?
Vishnu said:
8 years ago
Can anyone explain clearly?
Chandra said:
8 years ago
How this will occurs?
Maya said:
8 years ago
@6 difference b/w level is (100.25-99.25)=1.
@7 RL=100.25+0.25=100.5.
So difference= 102-100.5=1.5,
let x be distance at no filling or cutting,
distance b/w 7 and 6 is 30,
By similar triangle,
1 -> x,
1.5 ->30-x.
@7 RL=100.25+0.25=100.5.
So difference= 102-100.5=1.5,
let x be distance at no filling or cutting,
distance b/w 7 and 6 is 30,
By similar triangle,
1 -> x,
1.5 ->30-x.
(1)
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