Civil Engineering - Construction Management - Discussion

Discussion Forum : Construction Management - Section 2 (Q.No. 29)
29.
For the network shown in the given figure, the expected time for the activity
1-2 is 4
2-3 is 7
3-4 is 8
all the above.
Answer: Option
Explanation:

Expected time = (Pessimistic value + 4*most likely value + Optimistic value)/6.

1-2 is 4.

2-3 is 7.

3-4 is 8.

Discussion:
7 comments Page 1 of 1.

Annepu Viswanth said:   9 years ago
[3 + (4 * 4) + 5]/4 = 4.
[5 + (4 * 7) + 9]/4 = 7.
[6 + (4 * 8) + 10]/4 =8.

There fore A, B, C are correct i.e., option D is the answer.

Annepu Viswanth said:   9 years ago
[3 + (4 * 4) + 5]/4 = 4.
[5 + (4 * 7) + 9]/4 = 7.
[6 + (4 * 8) + 10]/4 =8.

There fore A, B, C are correct i.e., option D is the answer.

Annepu Viswanth said:   9 years ago
[3 + (4 * 4) + 5]/4 = 4.
[5 + (4 * 7) + 9]/4 = 7.
[6 + (4 * 8) + 10]/4 =8.

There fore A, B, C are correct i.e., option D is the answer.

Pawan said:   8 years ago
Its [3+4 * 4+5] ÷ 6 =4.

And accordingly others will be calculated i.e. 7 & 8 respectively.

Roco said:   8 years ago
(ta+4tm+tp)÷6 is the formula.

Lalitha said:   7 years ago
Right (ta+4tm+tp)/6 is the formula.

Muhammad Junaid Michaelson said:   5 years ago
@Lalitha.

You're 100% right. In the Denominator its is "6" NOT "4".

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