Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 5 (Q.No. 29)
29.
For a concrete mix 1:3:6 and water cement ratio 0.6 both by weight, the quantity of water required per bag, is
Discussion:
57 comments Page 6 of 6.
Kamran said:
10 years ago
Why we take aggregate 150 kg?
3 times of cement? Explain please?
3 times of cement? Explain please?
Nitu bharti said:
10 years ago
Water required = (5% of aggregate + 30% of cement)*w/c.
Cement per bag = 50 kg.
Aggregate = 50*3 = 150 kg.
5% of aggregate = 7.5 kg.
30% of cement= 15 kg.
Water required = (15+7.5)*0.6 = 13.5 kg which may be approximately 14 kg.
Cement per bag = 50 kg.
Aggregate = 50*3 = 150 kg.
5% of aggregate = 7.5 kg.
30% of cement= 15 kg.
Water required = (15+7.5)*0.6 = 13.5 kg which may be approximately 14 kg.
Robert said:
10 years ago
How did you rear get them I don't get it?
P.s said:
1 decade ago
See 30%of cement means 0.3*50 kg = 15 kg.
5% of fine aggregate 0.05*150 = 7.5 kg.
0.6*(15+7.5) = 13.5 kg+14 kg.
5% of fine aggregate 0.05*150 = 7.5 kg.
0.6*(15+7.5) = 13.5 kg+14 kg.
Suman said:
1 decade ago
0.6 means 60 liter water per 100 kg cement as 1 bag of cement contains 50 kg of cement.
So 60/2 = 30 liter water required per bag of cement.
So 60/2 = 30 liter water required per bag of cement.
Prahumac said:
1 decade ago
Can anybody please give a proper explanation for this one?
(1)
Kavita said:
1 decade ago
Please solve this problem. How this answer comes?
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