Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 5 (Q.No. 29)
29.
For a concrete mix 1:3:6 and water cement ratio 0.6 both by weight, the quantity of water required per bag, is
10 kg
12 kg
14 kg
16 kg
20 kg
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
57 comments Page 5 of 6.

Mehebub said:   9 years ago
@Salman.

But here told ratio 1:3:6,

Where, 1=Cement, 3=Sand, and 6=Stone.
Therefore Sand + Stone = Aggregate.
So, sum total 3 + 6 = 9. [50x9 = 450Kg].

Ar. SALMAN AFAQUE said:   9 years ago
1:3:6, so we multiply by 1*50 Kg cement and 3 fine aggregate * 50 kg, so.

We get 150 kg fine aggregate.

Rakesh Nhavkar said:   9 years ago
It's Thumb Rules for deciding the quantity of water in concrete:

(i) Weight of water = 28% of the weight of cement + 4% of the weight of total aggregate.

(ii) Weight of water = 30% of the weight of cement + 5% of the weight of total aggregate.

Shivkumar said:   9 years ago
Yeah, I agree with the answer 30.

Shubham mehta said:   9 years ago
Yeah, that's the Water is required 60% of the cement means if we are considering the 1 bag of 50kg then for water. It will become (60/100) 50 = 30 litres.

Ajay Agnihotri said:   9 years ago
However, I believe that the density of cement is 1440 Kg/Cum.

Therefore, the volume of a 50 kg cement bag works out to be [ 50/1440 ]*1000 = 34.722 Liters.

Kayathri said:   9 years ago
Why we are taking 5% of aggregate and 30% of cement?

NIKUNJ said:   9 years ago
Water required per bag means:

Cement bag = 50 kg.

W/c ratio = 0.6.

Water = 50 x 0.6.

Hence water = 30 kg.

If we assume water absorption in calculation then water require more than 30 kg.

Abhi said:   10 years ago
Its wrong answer is 30 kg.

How can we take water for aggregate if nothing is mentioned?

S. kumar said:   10 years ago
3 times of cement is fine sand, aggregate is 6 times actually. How you can take aggregate 3 times? Explain please?


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