Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 2 (Q.No. 37)
37.
The internal dimensions of a ware house are 15 m x 5.6 m, and the maximum height of piles is 2.70 m, the maximum number of bags to be stored in two piles, are
1500 bags
2000 bags
2500 bags
3000 bags
4000 bags
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
45 comments Page 5 of 5.

Achhami baddo said:   6 years ago
Total volume of room= 15*5.6*2.7 =226.8 m3,
Space between two piles = 1.6m,
Total volume of space = 15*1.6*2.7 =64.8 m3,
Effective volume = 226.8-64.8 m3= 162 m3,
Volume of one bag cement = 0.054m3.
No's of bag to be stored = 162/0.054= 3000bags.

So the correct answer is option "C" 3000 bags.

Tiger said:   6 years ago
={(1500-60)x(560-80-60)x270}/(3000x18).
= 3024.
= 3000 is the Answer.

Anjali said:   6 years ago
14.7*5.3*2.7 ÷ 035 = 3005.

Mansoor Khan said:   6 years ago
It's overall dimensions of the warehouse, so we need to convert it to the effective area by subtracting lengths from sidewalls.
Effective dimensions of Warehouse:
=> (15 -.6 -.6)= 13.8m.
=> (5.6 -.6 -.6) = 4.4m.
> Hight of pile = 2.7m.
The effective dimensions of Cement Bag:
Area of 1 cement beg = .3 sqm,
Height of 1cement beg = .18 sqm.

Calculation:
=>(13.8 * 4.4* 2.7)/(.3*.18)= 3036 bags.

Beewaek Mandal said:   6 years ago
The answer is 3000 Bags.

Internal dim.Area=15*5.6*2.70=226.8m3.

Ext. Dim area=15*1.6*2.70=64.8m3 (1.6 is bcoz one piles spacing 0.8m for two piles=1.6m)
Effective= Int-Ext= 162.

For one bag cement= 0.3 sq.m Ht= 0.18m.
No = 162/0.18 =3000.


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