Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 37)
37.
The internal dimensions of a ware house are 15 m x 5.6 m, and the maximum height of piles is 2.70 m, the maximum number of bags to be stored in two piles, are
Discussion:
45 comments Page 4 of 5.
Jivan shahi said:
2 years ago
The Width of Pile = 1.6m,
So, width of warehouse = 5.6 - 1.6 = 4
Now volume=15 * 4* 2.7 = 162
Now, the volume of one bag = .054.
So, 162/.054 = 3000 bags.
So, width of warehouse = 5.6 - 1.6 = 4
Now volume=15 * 4* 2.7 = 162
Now, the volume of one bag = .054.
So, 162/.054 = 3000 bags.
(3)
Sai said:
8 years ago
7 bags for 1 cum concrete.
15 * 5.6 * 2.7 = 226.8 cum.
226.8 * 7 = 1587.6 cum for 1 pile.
For 2 piles 2 * 1587.6 = 3175.2 bags.
15 * 5.6 * 2.7 = 226.8 cum.
226.8 * 7 = 1587.6 cum for 1 pile.
For 2 piles 2 * 1587.6 = 3175.2 bags.
Satyam said:
2 years ago
L = 15-0.6-0.6 = 13.8
B = 5.6 - 0.6 - 0.6 = 4.4
H = 2.7
13.8 × 4.4 × 2.7/0.3 × 0.18 = 3000 bag.
B = 5.6 - 0.6 - 0.6 = 4.4
H = 2.7
13.8 × 4.4 × 2.7/0.3 × 0.18 = 3000 bag.
(6)
Sharad said:
1 decade ago
How this answer is possible please explain with size of cement bag or volume of cement bag?
Tiger said:
6 years ago
={(1500-60)x(560-80-60)x270}/(3000x18).
= 3024.
= 3000 is the Answer.
= 3024.
= 3000 is the Answer.
Pratik anil Chaudhary said:
5 years ago
What amount of floor space will one bag of cement occupy? Tell me.
(1)
Tanveer said:
7 years ago
Then, what is the answer? Please explain it correctly.
Njr said:
2 years ago
2100 for a single pile.
So, the right answer is 2500.
So, the right answer is 2500.
(1)
Asif wazir said:
7 years ago
(5.6-0.6-0.6) x (15-0.6-0.6) x 2.7/(0.3x.18) = 3036.
Sabin said:
7 years ago
Give the explanation of the correct answer, please.
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