Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 1 (Q.No. 37)
37.
If X, Y and Z are the fineness modulli of coarse, fine and combined aggregates, the percentage (P) of fine aggregates to combined aggregates, is
Discussion:
20 comments Page 1 of 2.
PRASENJIT said:
7 years ago
(CALCULATING RATIO OF FINE AGGREGATE TO COARSE AGGREGATE).
Let "x1" is the percentage of fine aggregate to be combined with coarse aggregate. x can be calculated using the formula given below.
x = [(F2-F)/(F-F1)] * 100.
Where,
F1 = Fineness modulus value of the fine aggregate.
F2 = Fineness modulus value of coarse aggregate.
F = Fineness modulus value of the combined aggregate.
After finding the percentage of fine aggregate to be combined with the coarse aggregate by the above formula, their proportion can be calculated.
Let "x1" is the percentage of fine aggregate to be combined with coarse aggregate. x can be calculated using the formula given below.
x = [(F2-F)/(F-F1)] * 100.
Where,
F1 = Fineness modulus value of the fine aggregate.
F2 = Fineness modulus value of coarse aggregate.
F = Fineness modulus value of the combined aggregate.
After finding the percentage of fine aggregate to be combined with the coarse aggregate by the above formula, their proportion can be calculated.
Beekram Lama said:
3 years ago
The given answer is the percentage of fine aggregate to the coarse aggregate but the question is to calculate the percentage of fine aggregate to the total aggregate.
Let p:1 be the proportion of fine to coarse aggregate so the total proportion of combined aggregate is (p+1).
Now p*Y+1*X=(1+p) * Z.
on solving we get p=(Z-X)/(Y-Z).
Now to get the proportion of fine to the total aggregate,
p/(p+1) comes out to be (X-Z)/(X-Y).
And in percentage just multiply it by 100.
Let p:1 be the proportion of fine to coarse aggregate so the total proportion of combined aggregate is (p+1).
Now p*Y+1*X=(1+p) * Z.
on solving we get p=(Z-X)/(Y-Z).
Now to get the proportion of fine to the total aggregate,
p/(p+1) comes out to be (X-Z)/(X-Y).
And in percentage just multiply it by 100.
(3)
Nirav Bhatt said:
1 decade ago
The fineness Modulus (FM) of Coarse aggregate is higher than combined and fine aggregate. The FM of fine aggregates is lowest. And FM of combined aggregate is in between.
Here, X = Coarse aggregate = Largest value.
Y = Fine aggregate = Lowest value.
Z = Combined aggregate = Intermediate value.
Compare it with the answer. You will get the required information.
Here, X = Coarse aggregate = Largest value.
Y = Fine aggregate = Lowest value.
Z = Combined aggregate = Intermediate value.
Compare it with the answer. You will get the required information.
Chetan said:
8 years ago
No, answer is correct, according to question. @Darshan H A 100%correct.
Let FA/CA=m then the ratio of FA with combined aggregate is m/ (m+1).
Now solve you get the desired answer.
Let FA/CA=m then the ratio of FA with combined aggregate is m/ (m+1).
Now solve you get the desired answer.
Virender paul said:
7 years ago
Answer is correct.
Because coaser particle will be greater than combined or finer so answer should be coarser-combined/combinef-fine.
Because coaser particle will be greater than combined or finer so answer should be coarser-combined/combinef-fine.
DARSHAN H A said:
9 years ago
Question should be percentage of fine aggregate to coarse aggregate not combined aggregate.
Dimpi said:
10 years ago
Z- Combined Aggregate. (Both fine & Coarse), So value should be highest?
Garry said:
8 years ago
None of the above is correct.
Correct is, (X-Z)/(X-Y).
Correct is, (X-Z)/(X-Y).
Nayandeep said:
9 years ago
B and E options are same if we take sign common.
Pratusha Shankar Arepelli said:
4 years ago
How to calculate it? Please explain in detail.
(1)
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