Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 1 (Q.No. 2)
2.
If 1500 g of water is required to have a cement paste 1875 g of normal consistency, the percentage of water is,
20%
25%
30%
35%
40%
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
95 comments Page 3 of 10.

Zia said:   1 decade ago
Well prof is right.

While wt.of cement/wt of water will give ratio not %.

Gali nagendra said:   1 decade ago
0.85*consistency*wt.of cement = wt.of water.

Kiran birajdar said:   1 decade ago
Given data:

Weight of cement = 1875gm.
Weight of water = 1500gm.

Solution:

Weight of cement = 1875-1500 = 375gm.

% of water = (Weight of cement/Weight of water)*100 = (1875-1500/1500)*100 = 25%.

Ramesh said:   1 decade ago
I am agree with Prof.P. Rajayogan.

Khemraj Regmi said:   1 decade ago
My question for the participants of this discussion forum is that where is the formula for the percentage water as weight of cement divided by weight of water?

I agree with Prof. P. Rajayogan. Thank you Prof. I have the long time confusion for this question. I am also thinking so but I am not getting single one to report this question like that.
(1)

Mohd sarfraz said:   1 decade ago
It is very simple water percentage is 25 If any guy doubt it than any other contact me than I will prove it.

Himanshu jain said:   1 decade ago
According to this question.

Weight of water = 1500 g.

Weight of cement paste = 1875 g.

Percentage age of water = (Weight of water/Weight of paste)x100%.

i.e 5 = (1500/1875)x100.

=> 80%.

GAURAV GIRI said:   1 decade ago
Weight of cement = 1875-1500 = 375.

So % of water = 375/wt of water.

= 375/1500*100.
= 25%.

Abukhaled said:   1 decade ago
Wt. of water = 1500 gm.

Wt. of cement = 1875-1500 = 375 gm.

w/c = 1500/375 = 40%.

This means each 1 gm of cement needs 4 gms of water.

Tony said:   1 decade ago
But, weight of water is 1500g.

So % = Weight of water/Weight of paste*100.

= 1500/1875*100 = 80%.


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