Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 1 (Q.No. 2)
2.
If 1500 g of water is required to have a cement paste 1875 g of normal consistency, the percentage of water is,
Discussion:
95 comments Page 10 of 10.
Sagar said:
1 decade ago
What in earth, the percentage of water = wt. of cement/wt. of water.
% of water would be (wt. of water/wt. of paste)*100.
% of water would be (wt. of water/wt. of paste)*100.
Tony said:
1 decade ago
But, weight of water is 1500g.
So % = Weight of water/Weight of paste*100.
= 1500/1875*100 = 80%.
So % = Weight of water/Weight of paste*100.
= 1500/1875*100 = 80%.
Abukhaled said:
1 decade ago
Wt. of water = 1500 gm.
Wt. of cement = 1875-1500 = 375 gm.
w/c = 1500/375 = 40%.
This means each 1 gm of cement needs 4 gms of water.
Wt. of cement = 1875-1500 = 375 gm.
w/c = 1500/375 = 40%.
This means each 1 gm of cement needs 4 gms of water.
GAURAV GIRI said:
1 decade ago
Weight of cement = 1875-1500 = 375.
So % of water = 375/wt of water.
= 375/1500*100.
= 25%.
So % of water = 375/wt of water.
= 375/1500*100.
= 25%.
Himanshu jain said:
1 decade ago
According to this question.
Weight of water = 1500 g.
Weight of cement paste = 1875 g.
Percentage age of water = (Weight of water/Weight of paste)x100%.
i.e 5 = (1500/1875)x100.
=> 80%.
Weight of water = 1500 g.
Weight of cement paste = 1875 g.
Percentage age of water = (Weight of water/Weight of paste)x100%.
i.e 5 = (1500/1875)x100.
=> 80%.
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