Civil Engineering - Building Materials - Discussion
Discussion Forum : Building Materials - Section 2 (Q.No. 30)
30.
For slaking of 10 kg of CaO, the theoretical amount of water is
Discussion:
16 comments Page 2 of 2.
Prabhakar maurya said:
5 years ago
Cao = 56,
H2o = 18,
56 = 18,
1 = [18/56].
10kg lime = (18/56)*10=3.2kg water.
H2o = 18,
56 = 18,
1 = [18/56].
10kg lime = (18/56)*10=3.2kg water.
(12)
Ravi said:
5 years ago
How much time it will take Cao to slake?
Ravi chandra said:
5 years ago
How we introduce the CaO to the clay specimen to find the swell in the specimen due to slaking? Please explain to me.
Nasar khan said:
4 years ago
How Cao =56 and H20 = 18? Please explain.
(1)
M.ishaq said:
3 years ago
Atomic weight of these elements.
Ca = 40,
O = 16,
H = 1.
Cao = 40 + 16 = 56.
H2O = (2*1)+16 = 18.
Ca = 40,
O = 16,
H = 1.
Cao = 40 + 16 = 56.
H2O = (2*1)+16 = 18.
(3)
Avinash said:
3 years ago
How much h20 is needed to make 10kg of quick lime to slaked lime? Anyone give me the solution, please.
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