Civil Engineering - Building Materials - Discussion
Discussion Forum : Building Materials - Section 2 (Q.No. 30)
30.
For slaking of 10 kg of CaO, the theoretical amount of water is
Discussion:
16 comments Page 1 of 2.
Prabhakar maurya said:
5 years ago
Cao = 56,
H2o = 18,
56 = 18,
1 = [18/56].
10kg lime = (18/56)*10=3.2kg water.
H2o = 18,
56 = 18,
1 = [18/56].
10kg lime = (18/56)*10=3.2kg water.
(12)
Dhanu said:
8 years ago
Theoretically, the requirement of water for slaking of lime is 32 per cent of the weight of CaO.
Source : S.K Duggal.
Source : S.K Duggal.
(5)
M.ishaq said:
3 years ago
Atomic weight of these elements.
Ca = 40,
O = 16,
H = 1.
Cao = 40 + 16 = 56.
H2O = (2*1)+16 = 18.
Ca = 40,
O = 16,
H = 1.
Cao = 40 + 16 = 56.
H2O = (2*1)+16 = 18.
(3)
Diwakar naik said:
8 years ago
Theoretically, the requirement of water for slaking of lime is 32% weight of CaO.
i.e for 10kg lime 3.2 kgs of water required for slaking.
i.e for 10kg lime 3.2 kgs of water required for slaking.
(2)
Nasar khan said:
4 years ago
How Cao =56 and H20 = 18? Please explain.
(1)
M.A MURTAZA said:
1 decade ago
Since the molecular mass of CaO is 0.056 kg and molecular mass of H20 is 0.018 kg. Hence applying unitary method method we get 3.2 kg.
Sharat said:
1 decade ago
What is unitary method?
Radhakrishna said:
10 years ago
It means scaling down one of the variables to a single unit, i.e. "1". Didn't make you satisfy, ok here is an example if six coins weight is 66. Then what is the weight of 17 coins?
Consider the weight of one coin first.
1 coin weighs 66/6 = 11.
Now it is easy to calculate the cost of seventeen coins.
17 coins weigh 17 x 11 = 187.
Consider the weight of one coin first.
1 coin weighs 66/6 = 11.
Now it is easy to calculate the cost of seventeen coins.
17 coins weigh 17 x 11 = 187.
Ranjit kumar NCE CHANDI said:
10 years ago
CaO + H2O = Ca(OH)2.
56g 18g. 74g.
Since 56g CaO requires 18g water.
Hence 10 kg requires = (18/56)*10 = 3.214 kg.
56g 18g. 74g.
Since 56g CaO requires 18g water.
Hence 10 kg requires = (18/56)*10 = 3.214 kg.
Prashant Pawar said:
9 years ago
CaO = 0.056 Kg and H2O = 0.018 Kg,
Therefore, 0.056 = 0.018,
10 = (X),
By Solving (X) = (10 X 0.018)/0.056,
= 3.214 Kg.
Therefore, 0.056 = 0.018,
10 = (X),
By Solving (X) = (10 X 0.018)/0.056,
= 3.214 Kg.
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