Discussion :: Building Materials - Section 2 (Q.No.30)
For slaking of 10 kg of CaO, the theoretical amount of water is
Answer: Option C
No answer description available for this question.
|M.A Murtaza said: (Jun 16, 2015)|
|Since the molecular mass of CaO is 0.056 kg and molecular mass of H20 is 0.018 kg. Hence applying unitary method method we get 3.2 kg.|
|Sharat said: (Jul 25, 2015)|
|What is unitary method?|
|Radhakrishna said: (Jan 4, 2016)|
|It means scaling down one of the variables to a single unit, i.e. "1". Didn't make you satisfy, ok here is an example if six coins weight is 66. Then what is the weight of 17 coins?
Consider the weight of one coin first.
1 coin weighs 66/6 = 11.
Now it is easy to calculate the cost of seventeen coins.
17 coins weigh 17 x 11 = 187.
|Ranjit Kumar Nce Chandi said: (Jan 16, 2016)|
|CaO + H2O = Ca(OH)2.
56g 18g. 74g.
Since 56g CaO requires 18g water.
Hence 10 kg requires = (18/56)*10 = 3.214 kg.
|Prashant Pawar said: (Aug 27, 2016)|
|CaO = 0.056 Kg and H2O = 0.018 Kg,
Therefore, 0.056 = 0.018,
10 = (X),
By Solving (X) = (10 X 0.018)/0.056,
= 3.214 Kg.
|M.S. Faisal said: (Nov 2, 2016)|
|Cao = 56gm and H20 =18gm.
The ratio of this
Rch = Cao/H2o = 56/18 = 3.112.
There for X = 10x1/Rch.
X = 10x1/3.112 = 3.21.
|Dhanu said: (Sep 7, 2017)|
|Theoretically, the requirement of water for slaking of lime is 32 per cent of the weight of CaO.
Source : S.K Duggal.
|Diwakar Naik said: (Dec 15, 2017)|
|Theoretically, the requirement of water for slaking of lime is 32% weight of CaO.
i.e for 10kg lime 3.2 kgs of water required for slaking.
|Manoj said: (Sep 14, 2019)|
|What is Slacking?|
|Suman said: (Dec 11, 2019)|
|Slaking is of the process by adding water of turning the traditional building material lime into burned lime.|
|Prabhakar Maurya said: (Aug 18, 2020)|
|Cao = 56,
H2o = 18,
56 = 18,
1 = [18/56].
10kg lime = (18/56)*10=3.2kg water.
|Ravi said: (Nov 13, 2020)|
|How much time it will take Cao to slake?|
|Ravi Chandra said: (Nov 13, 2020)|
|How we introduce the CaO to the clay specimen to find the swell in the specimen due to slaking? Please explain to me.|
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