Civil Engineering - Building Construction - Discussion
Discussion Forum : Building Construction - Section 3 (Q.No. 27)
27.
If height of the first storey of a building is 3.2 m and riser is 13 cm, the number of treads required, is
Discussion:
20 comments Page 1 of 2.
Arif said:
1 decade ago
First of all covert height in cm so,
3.2*100 = 320 after that one riser is 13 cm.
320/13 = 24.6.
3.2*100 = 320 after that one riser is 13 cm.
320/13 = 24.6.
Tojum Ete said:
8 years ago
What is the exact formula? anyone please explain me.
Roy said:
8 years ago
Height of one flight = 320/2=160 cm.
No of rises in one flight=160/13=app. 13,so no of threads in one flight=13-1=12, so total no of tread in one storey =12*2=24.
No of rises in one flight=160/13=app. 13,so no of threads in one flight=13-1=12, so total no of tread in one storey =12*2=24.
Naveen B said:
8 years ago
3.20/0.13 = 25 (Height of a building/ riser).
For each storey, No of threads = 25 - No of storeys (Here it is 1).
i.e 25-1 = 24.
If it is a 2-storey building, then No of threads equal to 25-2 = 23 and Vice versa.
For each storey, No of threads = 25 - No of storeys (Here it is 1).
i.e 25-1 = 24.
If it is a 2-storey building, then No of threads equal to 25-2 = 23 and Vice versa.
Manav kumar said:
7 years ago
If multi-storey building than what to do? Please explain.
Nanu said:
7 years ago
What about for 2 flights?
Ujjol said:
6 years ago
Yes, you are right, thanks @Roy.
GOPAL said:
6 years ago
Well said, Thanks @Roy.
Ajay kumar yadav said:
5 years ago
Thanks for a helpful answer.
Kisore said:
5 years ago
Thanks @Roy.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers