### Discussion :: Applied Mechanics - Section 3 (Q.No.23)

Eeranna said: (Aug 8, 2016) | |

m.i about centroidal axis = bd3/12. m.i about its base = bd3/3. The ratio between them is 3/4. |

Anonymous said: (Dec 3, 2016) | |

Moment of inertia about base = bh^3/3 Moment of inertia about C.G = bh^3/12 Ratio = (1/12) * (3/1) = 1:4 |

Mehta said: (Oct 15, 2018) | |

Moment of Inertia @ Centroidal Axis = (bd^3) / 12. Moment of inertia @ Base Axis = (bd^3)/3. Ratio between (Centroidal Axis / Base Axis) = [{(bd^3)/12}/{(bd^3)/3}] Ratio = 3 / 12. The answer should equal to 1/4. Answer - Option A is the correct answer. |

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