Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 3 (Q.No. 45)
45.
A satellite is said to move in a synchronous orbit if it moves at an altitude of 36, 000 km with a maximum velocity of about
Discussion:
3 comments Page 1 of 1.
Ruturaj patil said:
7 years ago
How to solve this?
Twinkle Vinu said:
6 years ago
Distance to be covered by the satellite = (equitorial radius of earth + 36000)* 2π.
Time for covering this distance = 24 hrs (geosynchronous satellite),
Required velocity= distance/ time = 11000 km/h approx.
Time for covering this distance = 24 hrs (geosynchronous satellite),
Required velocity= distance/ time = 11000 km/h approx.
Jinish patel said:
6 years ago
A geosynchronous satellite is a satellite in geosynchronous orbit, with an orbital period the same as the Earth's rotation period (24 hours). Such a satellite returns to the same position in the sky after each sidereal day, and over the course of a day traces out a path in the sky so T=24 hours.
Distance covered by any satellite = (radius of the earth+traveling distance by satellite)*2*3.14.
=(6,371 km+36000)x2x3.14.
=266089.88 km.
Velocity= distance/time.
= 266089/24.
= 11,087 km/hr.
Says 11000 km/hr.
Distance covered by any satellite = (radius of the earth+traveling distance by satellite)*2*3.14.
=(6,371 km+36000)x2x3.14.
=266089.88 km.
Velocity= distance/time.
= 266089/24.
= 11,087 km/hr.
Says 11000 km/hr.
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