Discussion :: Applied Mechanics - Section 3 (Q.No.45)
|Ruturaj Patil said: (Aug 27, 2018)|
|How to solve this?|
|Twinkle Vinu said: (Apr 13, 2019)|
|Distance to be covered by the satellite = (equitorial radius of earth + 36000)* 2π.
Time for covering this distance = 24 hrs (geosynchronous satellite),
Required velocity= distance/ time = 11000 km/h approx.
|Jinish Patel said: (Dec 10, 2019)|
|A geosynchronous satellite is a satellite in geosynchronous orbit, with an orbital period the same as the Earth's rotation period (24 hours). Such a satellite returns to the same position in the sky after each sidereal day, and over the course of a day traces out a path in the sky so T=24 hours.
Distance covered by any satellite = (radius of the earth+traveling distance by satellite)*2*3.14.
= 11,087 km/hr.
Says 11000 km/hr.
Post your comments here:
Email : (optional)
» Your comments will be displayed only after manual approval.