Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 2 (Q.No. 3)
3.
Newton's law of Collision of elastic bodies states that when two moving bodies collide each other, their velocity of separation
Discussion:
3 comments Page 1 of 1.
Chinu said:
9 years ago
Please explain it.
Suresh reddy said:
6 years ago
Coefficient of restitution "e"=
[relative velocity of separation/relative velocity of approach]
For perfectly elastic there is no lose in bombardment.=> e=1,;;;;;
Where e is b/w 0<e1.
[relative velocity of separation/relative velocity of approach]
For perfectly elastic there is no lose in bombardment.=> e=1,;;;;;
Where e is b/w 0<e1.
Atharva kale said:
5 years ago
Here,
For Elastic body;
sep. vel = approach velocity.
So, as sep vel. increases then approach velocity also increases.
And also e = 1 = s.v/a.v.
So the output should be both A & C.
For Elastic body;
sep. vel = approach velocity.
So, as sep vel. increases then approach velocity also increases.
And also e = 1 = s.v/a.v.
So the output should be both A & C.
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