Civil Engineering - Applied Mechanics - Discussion

3. 

Newton's law of Collision of elastic bodies states that when two moving bodies collide each other, their velocity of separation

[A]. is directly proportional to their velocity of approach
[B]. is inversely proportional to their velocity of approach
[C]. bears a constant ratio to their velocity of approach
[D]. is equal to the sum of their velocities of approach.

Answer: Option C

Explanation:

No answer description available for this question.

Chinu said: (Jan 20, 2017)  
Please explain it.

Suresh Reddy said: (Mar 22, 2019)  
Coefficient of restitution "e"=
[relative velocity of separation/relative velocity of approach]
For perfectly elastic there is no lose in bombardment.=> e=1,;;;;;
Where e is b/w 0<e1.

Atharva Kale said: (Sep 25, 2020)  
Here,
For Elastic body;
sep. vel = approach velocity.
So, as sep vel. increases then approach velocity also increases.

And also e = 1 = s.v/a.v.
So the output should be both A & C.

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