### Discussion :: Applied Mechanics - Section 1 (Q.No.12)

Himanshu said: (Jun 26, 2013) | |

How this is possible ? the double differentiation of equation is 6t+2. |

Zuber said: (Aug 27, 2013) | |

x = t2(t+1). = t3+t. dx/dt = 3t2+1. d2x/dt2 = 6t+0. d2x/dt2 = Acceleration. So acceleration = 6t. |

Hitesh said: (Oct 4, 2013) | |

x = t2(t+1). x = t3+t2. dx/dt = 3t2+2t. d2x/dt2 = 6t+2. This is the required answer of the acceleration of at the any instant of time t. |

Alfifi said: (Feb 13, 2014) | |

x = t^2(t + 1)= t^3+t^2. V=dx/dt = 3t^2+2t. a = dV/dt = 6t+2. Answer is D. |

Saubhagya Nayak said: (Jun 13, 2014) | |

If x = t^2(t+1). i.e; x = t^3+t^2. Velocity v=dx/dt. i.e; 3t^2+2t. And then acceleration a=dv/dt. i.e; 6t+2. So the ans is no doubt option D. 6t+2. |

Pinjari Shahil said: (Aug 24, 2014) | |

x = t2(t+1). x = t3+t2. dx/dt = 3t2+2t. d2x/dt2 = 6t+2. This is the required answer of the acceleration but acceleration negative sign indicated. |

Piyush said: (Sep 12, 2014) | |

x = t^2 (t+1). x = (t^3)+(t^2). dx/dt = 3*t^2 + 2*t. dx^2/dt^2 = 6t + 2. |

Saurabh said: (Jan 22, 2015) | |

x = t^2(t+1). x = t^3+t^2. dx/dt = 3*t^2+2*t. d^2x/dt^2 = 6t+2. So answer is 6t+2 not 6t-2. |

Nilesh Gagare said: (Apr 27, 2017) | |

T2(t+1) T3+t. Diff w.r.t:t 3t2+1. Again diff w.r.t:t 6t. And the answer is 6t. |

Bvc said: (Jun 16, 2017) | |

x=t3+t2, dx/dt=3t2+2T, d2x/d2t=6T+2, Ans: D. |

Mohbat Khan Marri said: (Sep 13, 2017) | |

t^2(t+1). =t^3+t^2, dx/dt=3t^2+2t, dx^2/dt^2=6t+2. |

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