Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 1 (Q.No. 12)
12.
A particle moves along a straight line such that distance x traversed in t seconds is given by x = t2(t + 1), the acceleration of the particle, will be
Discussion:
13 comments Page 2 of 2.
Hitesh said:
1 decade ago
x = t2(t+1).
x = t3+t2.
dx/dt = 3t2+2t.
d2x/dt2 = 6t+2.
This is the required answer of the acceleration of at the any instant of time t.
x = t3+t2.
dx/dt = 3t2+2t.
d2x/dt2 = 6t+2.
This is the required answer of the acceleration of at the any instant of time t.
Zuber said:
1 decade ago
x = t2(t+1).
= t3+t.
dx/dt = 3t2+1.
d2x/dt2 = 6t+0.
d2x/dt2 = Acceleration.
So acceleration = 6t.
= t3+t.
dx/dt = 3t2+1.
d2x/dt2 = 6t+0.
d2x/dt2 = Acceleration.
So acceleration = 6t.
Himanshu said:
1 decade ago
How this is possible ? the double differentiation of equation is 6t+2.
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