Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 5 (Q.No. 49)
49.
If two equal forces of magnitude P act at an angle θ, their resultant, will be
Discussion:
14 comments Page 1 of 2.
Karthi said:
8 years ago
Can anyone tell the explanation of this answer?
Sagar said:
8 years ago
Please explain it.
Sunny said:
8 years ago
Please provide the explaination.
Karthik said:
8 years ago
Please anyone explain this.
Ankitsinh Rajput said:
7 years ago
Here is the answer.
If two forces P and Q acting at angle θ then resultant R=(P^2+Q^2+2P*Q*cosθ)^1/2.
now forces are equal i.e P=Q.
R=(2P^2+2P^2cosθ)^1/2
R=P{2(1+cosθ)}^1/2
now , 1+cosθ=2cos^2(θ/2).
R=P{4cos^2(θθ/2)}^1/2.
R=2Pcos(θ/2) i.e ANS.
If two forces P and Q acting at angle θ then resultant R=(P^2+Q^2+2P*Q*cosθ)^1/2.
now forces are equal i.e P=Q.
R=(2P^2+2P^2cosθ)^1/2
R=P{2(1+cosθ)}^1/2
now , 1+cosθ=2cos^2(θ/2).
R=P{4cos^2(θθ/2)}^1/2.
R=2Pcos(θ/2) i.e ANS.
(2)
K.srinu said:
7 years ago
Thanks @Ankitsinh.
Prathibha said:
7 years ago
Thanks for the explanation @Ankitsinh.
Abdul said:
7 years ago
@Ankitsinh.
Thanks for the explanation.
Thanks for the explanation.
Lakhan Bhavnani said:
6 years ago
Thanks for the explanation @Ankitsinh.
Bitam said:
6 years ago
Thanks for explaining @Ankitsin.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers