Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 5 (Q.No. 49)
49.
If two equal forces of magnitude P act at an angle θ, their resultant, will be
Discussion:
14 comments Page 2 of 2.
Ayush said:
6 years ago
Thanks all for explaining it.
Mukesh joshi said:
6 years ago
Thanks @Ankitsinh.
Engineers study said:
6 years ago
We know,
Cosx = cos^2(x/2) - sin^2(x/2).
Adding 1 both side,
1+ cosx = cos^2(x/2) - sin^2(x/2)+1.
We also know,
sin^2(x/2)+cos^2(x/2) = 1.
So,
1+ cosx = cos^2(x/2) - sin^2(x/2)+sin^2(x/2)+cos^2(x/2).
1+ cosx = 2cos^2(x/2).
Apply the value of 1+ cosx and proceed. Ankitsinh Rajput thanks, dude.
Cosx = cos^2(x/2) - sin^2(x/2).
Adding 1 both side,
1+ cosx = cos^2(x/2) - sin^2(x/2)+1.
We also know,
sin^2(x/2)+cos^2(x/2) = 1.
So,
1+ cosx = cos^2(x/2) - sin^2(x/2)+sin^2(x/2)+cos^2(x/2).
1+ cosx = 2cos^2(x/2).
Apply the value of 1+ cosx and proceed. Ankitsinh Rajput thanks, dude.
(1)
Sofeeya Mulla said:
5 years ago
Thanks @Ankita.
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