# Civil Engineering - Airport Engineering - Discussion

### Discussion :: Airport Engineering - Section 1 (Q.No.15)

15.

The reduced level of the proposed site of an air port is 2500 m above M.S.L. If the recommended length by I.C.A.O. for the runway at sea level is 2500 m, the required length of the runway is

 [A]. 2500 m [B]. 3725 m [C]. 3000 m [D]. 3250 m

Explanation:

No answer description available for this question.

 Aisha said: (Feb 1, 2016) How?

 Mandy said: (Mar 15, 2016) 2500+2500(0.07/300) = 3958 (put the nearest one).

 Suyagn Vaghela said: (Jun 5, 2016) Basic length is to be increased at rate 7% per 300m, Above MSL; So, correction is (7/100) X (2500/300) X 2500 = 1458 m. Then, total length is 3958m.

 Anfield said: (Mar 3, 2017) 7%is correct but per 300m is it? Please explain.

 Chhaya said: (May 4, 2017) @Anfield. 300 m Elevation 7% Length is increased.

 James said: (Oct 22, 2018) The Max length increase possible is 35%. So, 2500 x 0.35 + 2500 = 3375. Nearest safe length = 3725.

 Amber said: (Mar 6, 2019) (7/300) x 2500 = 58.33 above m.s.l. Basic runway length = 1.5833 x 2500. = 3958.25. = 3725 m (app).

 Aditya said: (Sep 27, 2019) How 2500? It should be 2100.

 Bishnu Pokhrel said: (Apr 29, 2020) 2500+2500*49÷100=3725. (2500÷300)for 300 of MSL 7% is added (7*7=49).