Civil Engineering - Airport Engineering - Discussion
Discussion Forum : Airport Engineering - Section 1 (Q.No. 26)
26.
The distance between main gears is 10 m, and the distance of nose gear from centre of main gears is 30 m. If the angle of turning is 60°, the distance of centre of rotation from the nearer main gear, is
Discussion:
7 comments Page 1 of 1.
Akshaya said:
5 years ago
Tuning radius = t * tan(90-turning angle)+b/2.
t=30 m,
b=10 m,
Turning radius = 60,
After solving turning radius = 22.32 m,
Distance of centre of rotation from nearer main gear = 22.32 - 10 = 12.32 m.
t=30 m,
b=10 m,
Turning radius = 60,
After solving turning radius = 22.32 m,
Distance of centre of rotation from nearer main gear = 22.32 - 10 = 12.32 m.
(2)
Rupesh said:
5 years ago
Tuning radius = t * tan(90-turning angle)+b/2.
t=30 m,
b=10 m,
Turning radius=60,
After solving turning radius=22.32 m,
Distance of centre of rotation from nearer main gear=22.32-10=12.32 m.
t=30 m,
b=10 m,
Turning radius=60,
After solving turning radius=22.32 m,
Distance of centre of rotation from nearer main gear=22.32-10=12.32 m.
(1)
Ajith said:
8 years ago
Tuning radius= t * tan(90-turning angle)+b/2.
t=30 m,
b=10 m,
Turning radius=60,
After solving turning radius=22.32 m,
Distance of centre of rotation from nearer main gear=22.32-10=12.32 m.
t=30 m,
b=10 m,
Turning radius=60,
After solving turning radius=22.32 m,
Distance of centre of rotation from nearer main gear=22.32-10=12.32 m.
(1)
Anirban said:
3 years ago
Please give the full description for the answer.
Harri said:
9 years ago
Please give the explanation of the problem.
Worrie said:
8 years ago
Sir, please give the explanation.
(1)
Vijay said:
8 years ago
Please give explaination.
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