Chemical Engineering - Stoichiometry - Discussion
Discussion Forum : Stoichiometry - Section 7 (Q.No. 41)
41.
What is the total pressure exerted by a mixture of 0.45 kg mole of benzene, 0.44 kg mole of toluene and 0.23 kg mole of o-xylene at 100°C, if their vapor pressures at 100°C are 1340, 560 and 210 mmHg respectively ?
Discussion:
2 comments Page 1 of 1.
Kalaiselvan said:
3 years ago
Ptotal = p1* x1+ p2 * x2 + p3 * x3.
= 1340 * 045/1.12 + 560 * .44/1.12 + 210 * .23/1.12,
= 801.5.
= 1340 * 045/1.12 + 560 * .44/1.12 + 210 * .23/1.12,
= 801.5.
(2)
Ansi said:
5 years ago
I think it should be 898.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers