Chemical Engineering - Mass Transfer - Discussion
Discussion Forum : Mass Transfer - Section 1 (Q.No. 2)
2.
In a solution containing 0.30 Kg mole of solute and 600 kg of solvent, the molality is
Discussion:
21 comments Page 3 of 3.
Poonam Rathod said:
1 decade ago
Molality = (solute/solvent) *100.
= (0.30/600) *1000.
= 0.50
= (0.30/600) *1000.
= 0.50
(1)
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