Chemical Engineering - Mass Transfer - Discussion
Discussion Forum : Mass Transfer - Section 3 (Q.No. 23)
23.
If f = moles of vapour present per mole of feed, then the slope of feed line is (Mcabe-Thiele method)
Discussion:
12 comments Page 1 of 2.
Mr Pegu said:
12 months ago
Anyone, explain me the correct answer.
Rajveer said:
1 year ago
According to me,
The answer will be (f-1)/f or -(1-f)/f.
The answer will be (f-1)/f or -(1-f)/f.
(1)
Ranjeet said:
2 years ago
Yes, it's (- q÷1-q).
TANMAY SHAH said:
3 years ago
'q' = mole fraction of liquid in the feed.
Then Slop = q/(q-1).
Now, q = 1-f Where f = mole fraction of vapour in the feed.
Then Slop = (f-1)/f.
If the feed is a saturated liquid i.e. it has no vapour, then q = 1 & f = 0. Then the slope of the q-line is infinite [a vertical line].
If the feed is a saturated vapour i.e. it has no liquid, then f = 1 & q = 0. Then the slope of the q-line is zero [ a horizontal line].
Then Slop = q/(q-1).
Now, q = 1-f Where f = mole fraction of vapour in the feed.
Then Slop = (f-1)/f.
If the feed is a saturated liquid i.e. it has no vapour, then q = 1 & f = 0. Then the slope of the q-line is infinite [a vertical line].
If the feed is a saturated vapour i.e. it has no liquid, then f = 1 & q = 0. Then the slope of the q-line is zero [ a horizontal line].
(5)
Amit Kumar kashyap said:
3 years ago
The answer should be [ (f-1) /f].q signifies the fraction of liquid in the feed.
Therefore, q = (1-f).
Now, slope of feed line is = q/(q-1) = (1-f)/(1-f-1) = (1-f)/(-f) = (f-1)/f.
Therefore, q = (1-f).
Now, slope of feed line is = q/(q-1) = (1-f)/(1-f-1) = (1-f)/(-f) = (f-1)/f.
(3)
Bashir said:
5 years ago
The correct answer is: f-1/f.
(3)
Bashir said:
5 years ago
Is there any difference between q-line and feed-line?
Chirag said:
5 years ago
The answer should be [ (1-f) /f].q is the fraction of liquid in the feed.
Therefore, q = (1-f).
Now, slope of feed line is = - q/(1-q) = - (1-f)/(1-1-f) = - (1-f)/(-f) = (1-f)/f.
Therefore, q = (1-f).
Now, slope of feed line is = - q/(1-q) = - (1-f)/(1-1-f) = - (1-f)/(-f) = (1-f)/f.
Tanna said:
6 years ago
q + f = 1
And slope is q / q-1
So in terms of f it should be
f-1 / f.
And slope is q / q-1
So in terms of f it should be
f-1 / f.
(1)
Neelam said:
7 years ago
It should be f-1/f.
(2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers