Chemical Engineering - Heat Transfer - Discussion

Discussion Forum : Heat Transfer - Section 1 (Q.No. 15)
15.
In Joule's experiment, an insulated container contains 20 kg of water initially at 25°C. It is stirred by an agitator, which is made to turn by a slowly falling body weighing 40 kg through a height of 4 m. The process is repeated 500 times. The acceleration due to gravity is 9.8 ms-2. Neglecting the heat capacity of agitator, the temperature of water (in °C) is
40.5
34.4
26.8
25
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
22 comments Page 1 of 3.

Samuel A said:   1 year ago
Thank you for giving an explanation.

Harika said:   3 years ago
Thankyou @Muhammed Ishaq.
(2)

Muhammed Ishak T N said:   3 years ago
@All.

Guys please try to solve this. The correct value for cp is 4180

By 1st law of thermodynamics;

Energy neither be created nor destroyed, it can be transformed from one form to another form.

So,
For 500 turns.
mgh = mcp( T2 - T1),
500*40*9.8*4 = 20*4180( T2-25),
By solving these we get;

784000 = 83600(T2-25),
T2-25 = 9.379,
So, T2 = 34.4,
(43)

Mohd Kasid said:   3 years ago
Thank you everyone for explaining the answer.
(2)

N.B. Parmar1753 said:   3 years ago
Thanks @Manu.

Ashish Yadav said:   4 years ago
Thanks everyone for explaining it.

Hadi muhammed said:   4 years ago
Thank you.

Jaykishor kumar yadav said:   6 years ago
Temperatures of heat exchangers depond upon the the flow of steam and pressure.

Melese said:   6 years ago
nmgh = mcpdt.
dT = T2-T1.
(1)

Selamu Abule said:   6 years ago
@Emeka.

Thanks for explaining.


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