Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 1 (Q.No. 15)
15.
In Joule's experiment, an insulated container contains 20 kg of water initially at 25°C. It is stirred by an agitator, which is made to turn by a slowly falling body weighing 40 kg through a height of 4 m. The process is repeated 500 times. The acceleration due to gravity is 9.8 ms-2. Neglecting the heat capacity of agitator, the temperature of water (in °C) is
Discussion:
22 comments Page 3 of 3.
Manu said:
1 decade ago
Heat supplied by falling body = Heat gained by water
m*g*h = m*cp* (T1 - T2)
500*40*9.81*4 =20*4184*(T1-25)
T1 = 34.4
m*g*h = m*cp* (T1 - T2)
500*40*9.81*4 =20*4184*(T1-25)
T1 = 34.4
Kshema said:
1 decade ago
Please explain
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