Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 1 (Q.No. 43)
43.
The heat flux (from outside to inside) across an insulating wall with thermal conductivity, K= 0.04 W/m.°K and thickness 0.16m is 10 W/m2. The temperature of the inside wall is - 5°C. The outside wall temperature is
Discussion:
15 comments Page 1 of 2.
Sumit Kumar said:
2 years ago
Q = KA(T2-T1)/dx.
Q = 10,
K = .04,
T1 = -5,
dx = .16,
A = 1.
10 = .04*(T2+5)/.16.
T2 + 5 = 40,
T2 = 40-5,
T2 = 35.
Q = 10,
K = .04,
T1 = -5,
dx = .16,
A = 1.
10 = .04*(T2+5)/.16.
T2 + 5 = 40,
T2 = 40-5,
T2 = 35.
(8)
Balaram said:
6 years ago
q = kdt/dx.
q = 10W/m^2.
K = 0.04.
10 = 0.04(t-5)/0.16.
t = 45deg c.
q = 10W/m^2.
K = 0.04.
10 = 0.04(t-5)/0.16.
t = 45deg c.
(1)
Vaishak said:
1 decade ago
q = kdt/dx.
q = 10W/m^2.
K = 0.04.
10 = 0.04(t+5)/0.16.
t = 35deg c.
q = 10W/m^2.
K = 0.04.
10 = 0.04(t+5)/0.16.
t = 35deg c.
Shan Rana said:
1 decade ago
@Vishal.
How you keep units consistent, here Temp is in Degree C and conoductivity in W/m. K ?
How you keep units consistent, here Temp is in Degree C and conoductivity in W/m. K ?
Rutu patel said:
1 decade ago
In equation dt gives the temperature difference. So it doesn't make any different weather you add 273 or not.
Sushil rajoria said:
1 decade ago
How you keep dt = (T+5) in presence of (T-5).
Nihar said:
1 decade ago
dT should be T-5 and the answer comes out to be 45°c. Please comment.
Madhuri said:
1 decade ago
The temperature given is minus five (-5) not hence temperature difference = t-(-5) = t+5.
Mahindra said:
10 years ago
The answer is 45 degree C.
Ccjayesh said:
10 years ago
Heat flux is 10 W/m^2. So answer is 35° C.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers