Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 1 (Q.No. 43)
43.
The heat flux (from outside to inside) across an insulating wall with thermal conductivity, K= 0.04 W/m.°K and thickness 0.16m is 10 W/m2. The temperature of the inside wall is - 5°C. The outside wall temperature is
Discussion:
15 comments Page 1 of 2.
Sumit Kumar said:
2 years ago
Q = KA(T2-T1)/dx.
Q = 10,
K = .04,
T1 = -5,
dx = .16,
A = 1.
10 = .04*(T2+5)/.16.
T2 + 5 = 40,
T2 = 40-5,
T2 = 35.
Q = 10,
K = .04,
T1 = -5,
dx = .16,
A = 1.
10 = .04*(T2+5)/.16.
T2 + 5 = 40,
T2 = 40-5,
T2 = 35.
(8)
Dipak Gund said:
5 years ago
dT = T2 -(-5) =T2 + 5.
So, the answer is 35.
So, the answer is 35.
Shankar said:
6 years ago
Here Q=-kdt/dx.
Balaram said:
6 years ago
q = kdt/dx.
q = 10W/m^2.
K = 0.04.
10 = 0.04(t-5)/0.16.
t = 45deg c.
q = 10W/m^2.
K = 0.04.
10 = 0.04(t-5)/0.16.
t = 45deg c.
(1)
Biswaranjan said:
6 years ago
@Khalid.
How you got the q value as 10?
How you got the q value as 10?
Amit shah said:
8 years ago
Use Fourier low for heat transfer by the condition.
Q= kdt/dx.
Q= kdt/dx.
Khalid.abed said:
8 years ago
q = - k dt/dx.
q = 10W/m2, 10 W/m2.
10 = 0.04(-5 - t)/0.16.
=> t = 35°C.
q = 10W/m2, 10 W/m2.
10 = 0.04(-5 - t)/0.16.
=> t = 35°C.
Ccjayesh said:
10 years ago
Heat flux is 10 W/m^2. So answer is 35° C.
Mahindra said:
10 years ago
The answer is 45 degree C.
Madhuri said:
1 decade ago
The temperature given is minus five (-5) not hence temperature difference = t-(-5) = t+5.
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