Chemical Engineering - Heat Transfer - Discussion

Discussion Forum : Heat Transfer - Section 1 (Q.No. 7)
7.
Steam consumption in kg/hr in case of an evaporator is given by (where, C & E are capacity the economy of the evaporator respectively)
C/E
E/C
CE
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 1 of 2.

Liul said:   2 years ago
Thanks for the description of the answer.
(1)

Muhammed Ishak T N said:   3 years ago
An easy way of solving:


Capacity = Vapour Generated/hr.

Economy = Vapour Generated/kg of steam.

Vapour generated is common in both;

So we can conclude that;

Capacity * hr = economy * kg of steam.
So, Capacity/Economy = Kg of steam/hr.
(29)

Joy said:   4 years ago
Thanks @Malik.
(1)

Om Prakash kannaujiya said:   6 years ago
Nice, Thanks @Malik.

Pankaj Sawai said:   6 years ago
Nice, Thanks @Malik.

Shire Leta said:   7 years ago
Capacity = steam generated/hour (kg/hr).

And economy = steam generated/steam utilized (kg of steam).
steam utilized(kg of steam)= steam generated/economy.

Then (kg of steam)*1/hr=(steam generated/economy)*1/hr
kg of steam/hr= (steam generated/hr)*1/economy.

Since steam generated/hr=capacity because capacity is a rate.
So steam utilized(kg of steam/hr) = capacity/economy.

Therefore steam utilised = capacity/economy.
(2)

Ritik gupta said:   7 years ago
Nice method, Thanks @Malik.

SALMAN Ali said:   7 years ago
Capacity = vapour generated/hr.

Mahesh said:   7 years ago
Nice answer @Malik.

Muhammad Arslan Jameel Malik said:   10 years ago
Capacity = Vapor generated/hr.

Economy = Vapor generated/kg of steam.

So, Kg of steam = Vapor generated/economy.

And dividing both sides by hour.

We get, Kg of steam/hr = (Vapor generated/hr)/economy.

Kg of steam/hr = Capacity/economy (C/E).
(2)


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