Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 9 (Q.No. 28)
28.
In a co-current double pipe heat exchanger used for condensing saturated steam over the inner tube, if the entrance and exit conditions of the coolant are interchanged, then the rate of condensation will
Discussion:
2 comments Page 1 of 1.
Philip said:
8 years ago
Co-current heat ex becomes countercurrent, right?
Can someone explain this problem? thank you.
Can someone explain this problem? thank you.
(2)
Suraj said:
4 years ago
Here the rate of heat transfer can be given by;
q(initial) = UAΔT(Lmtd for co-current).
q(final) = UAΔT(Lmtd for counter-current).
Since steam is condensing temperature on the shell side will be constant from inlet to the outlet so we get the same ΔT Lmtd for both the flow patterns.
Hence no effect on the rate of cooling.
Hope it helps.
q(initial) = UAΔT(Lmtd for co-current).
q(final) = UAΔT(Lmtd for counter-current).
Since steam is condensing temperature on the shell side will be constant from inlet to the outlet so we get the same ΔT Lmtd for both the flow patterns.
Hence no effect on the rate of cooling.
Hope it helps.
(1)
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