Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 9 (Q.No. 49)
49.
A centrifugal pump has the following specifications:
Power = 4 H.P.; Speed = 800 rpm
Head = 8 metres
Flow = 1000 litres/minutes.
If its speed is halved, then the new head will be __________ metres.
Power = 4 H.P.; Speed = 800 rpm
Head = 8 metres
Flow = 1000 litres/minutes.
If its speed is halved, then the new head will be __________ metres.
Discussion:
3 comments Page 1 of 1.
Grace said:
8 years ago
By Affinity law of pump.
(H1/H2)=(N1/N2)^2.
Given : Head H1=8m.
Speed N1=800 rpm, also given that speed is halved. Hence take N2=400rpm.
Now equation becomes,
(8/H2)=(800/400)^2,
New Head,H2=2m.
(H1/H2)=(N1/N2)^2.
Given : Head H1=8m.
Speed N1=800 rpm, also given that speed is halved. Hence take N2=400rpm.
Now equation becomes,
(8/H2)=(800/400)^2,
New Head,H2=2m.
(9)
Deeraj said:
8 years ago
Please anyone explain this.
(1)
Soni said:
9 years ago
Please, explain the answer.
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