Chemical Engineering - Chemical Reaction Engineering - Discussion

Discussion Forum : Chemical Reaction Engineering - Section 10 (Q.No. 11)
11.
In the hydrodealkylation of toluene to benzene, the following reactions occur:
C7H8 + H2 C6H6 + CH4
2C6H6 C12H10 + H2
Toluene and hydrogen are fed to a reactor in a molar ratio 1:5.80% of the toluene gets converted and the selectivity of benzene(defined as moles of benzene formed/moles of toluene converted) is 90%. The fractional conversion of hydrogen is
0.16
0.144
0.152
0.136
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

Suraj said:   4 years ago
Answer is 0.144.

Number of moles of hydrogen after the reaction is completed is 5-0.80+0.08=4.28

0.80 is subtracted because of the 80% conversion of toluene.
0.08 is added because, out of 0.80 moles of benzene to be formed, because of selectivity it forms only 0.72 moles and the rest is formed to hydrogen gas i.e. 0.80-072=0.08 according to reaction 2.
Now fractional conversion=1- 4.28/5=0.144.

Hope it helps.
(2)

Bhuvaneswari V said:   6 years ago
As per the equilibrium conversion process;
Z = (vi)ε ÷(ni 0).
The answer is 0.16.

As by using the conversion value of toluene epsilon is calculated.
By using which hydrogen value is calculated.

Shubham s said:   7 years ago
0.152 (c) is the right answer.
(1)

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