Chemical Engineering - Chemical Reaction Engineering - Discussion

Discussion Forum : Chemical Reaction Engineering - Section 1 (Q.No. 25)
25.
For a reaction of the type, , the rate of reaction (- rx) is given by
(K1+K1)CX
(K1+K2+K3)CX
K1CV - K2CX
(K1-K2)CX
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
9 comments Page 1 of 1.

Perry said:   7 months ago
Isn't -rx. interpreted as the rate of disappearance? Please explain to me.

Saheed said:   4 years ago
Yes, I agree @Mujahid Barde.

Because X appears as a product for k1.
(1)

Pathu said:   5 years ago
Positive sign for disapperance and negative for formation. So the answer is k2Cx - k1Cv.
(2)

Rohan said:   7 years ago
Yes, right. Thanks @Satya.
(1)

Mohit said:   7 years ago
Yes, right @Satya. Thanks all.
(1)

Ashish patel said:   7 years ago
I Agree @satya.
(1)

Mujahid Barde said:   7 years ago
The rate expression is independent on k3 since we are considering the rate of disappearance of X, and only k1 and k2 involve formation and disappearance of X respectively.

So you write the expression using positive sign for formation and negative for disappearance. So the answer is k1Cv-k2Cx.

Dssa said:   8 years ago
You are correct @Satya.

Satya said:   1 decade ago
k2cx-k1cv is the answer as he asked the rate of disappearance of X.
(2)

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