# Chemical Engineering - Chemical Reaction Engineering - Discussion

Discussion Forum : Chemical Reaction Engineering - Section 10 (Q.No. 4)

4.

With increase in temperature, the rate constant obeying Arhenious equation

Discussion:

12 comments Page 1 of 2.
Jaimin Pandya said:
5 years ago

k = k0 exp(-E/RT).

ln k =ln k0 + ln (-E/RT).

From the above equation, ln k is inversely prepositional to T.

So increase in T decrease in ln k.

Removing ln will exponentiation decrease in value of k.

ln k =ln k0 + ln (-E/RT).

From the above equation, ln k is inversely prepositional to T.

So increase in T decrease in ln k.

Removing ln will exponentiation decrease in value of k.

Rahul Saini said:
8 years ago

According to Arrhenius equation k = k0 exp(-E/RT). So rate constant should increase with increase in temperature.

Aadhar Chauhan said:
4 years ago

Option A is the right answer because K (rate constant) is directly proportional to the temperature.

Ankit saini said:
3 years ago

Yes T increase, k will also increase.

If k increase, then Ea decrease.

If k increase, then Ea decrease.

Rishika said:
4 years ago

According to me as T increases, K should increase.

SURESH said:
6 years ago

The Rate constant increase with temperature.

Satya said:
4 years ago

It is absolutely increased with temperature.

Raj Musale said:
5 years ago

Answer is option A.

Ref: Scott Fogler.

Ref: Scott Fogler.

Dipankar Kakati said:
8 years ago

The Rate constant increases.

Dev said:
7 years ago

Yes, it should increase.

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