Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 11 (Q.No. 12)
12.
At absolute zero temperature, the __________ of the gas is zero.
Discussion:
5 comments Page 1 of 1.
Rampravesh yadav said:
5 years ago
Agree, Thanks @Ashutosh YADAV.
Mahi said:
6 years ago
Here, Pv/=nRT.
Yadav said:
7 years ago
Agreed @Ashutosh Yadav.
Chemi said:
9 years ago
So, same can be done for pressure then it's uncertain.
(1)
Ashutosh yadav said:
1 decade ago
PV = nRT;.
Now dividing it by P we get V = nRT/P.
Now T=0;therefore from d above equation we get V=0;.
BUT this is only theoretically possible because it is difficult to obtain absolute zero.
Now dividing it by P we get V = nRT/P.
Now T=0;therefore from d above equation we get V=0;.
BUT this is only theoretically possible because it is difficult to obtain absolute zero.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers