Chemical Engineering - Chemical Engineering Thermodynamics - Discussion
Discussion Forum : Chemical Engineering Thermodynamics - Section 9 (Q.No. 21)
21.
A cylinder contains 640 gm of liquid oxygen. The volume occupied (in litres) by the oxygen, when it is released and brought to standard conditions (0°C, 760 mm Hg) will be __________ litres.
Discussion:
4 comments Page 1 of 1.
Rajkumar Pegu said:
3 years ago
Since, 1mol of O2 contains 22.4L.
So, 32gms of O2 contains 22.4/32L.
That implies,
640gms of O2 contains 22.4/32 * 640L = 448L.
So, 32gms of O2 contains 22.4/32L.
That implies,
640gms of O2 contains 22.4/32 * 640L = 448L.
Kamran Khan said:
3 years ago
@Athraa.
22.4 litre is a volume occupied by one mole of a gas at standard conditions.
22.4 litre is a volume occupied by one mole of a gas at standard conditions.
(1)
Athraa said:
3 years ago
@Sajjad.
22.4 What it is? Please explain it.
22.4 What it is? Please explain it.
Sajjad M said:
6 years ago
Mol O2 =640/32 = 20 mole.
Volume O2 (Litre) = 20*22.4 = 448 Litre.
Volume O2 (Litre) = 20*22.4 = 448 Litre.
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