Chemical Engineering - Chemical Engineering Basics - Discussion
Discussion Forum : Chemical Engineering Basics - Section 11 (Q.No. 39)
39.
The heat released by cooling one mole of copper from 400 K to room temperature (300 K) is (assume : Cp of copper is 23 J K-1mole-1)
Discussion:
1 comments Page 1 of 1.
AANAL said:
7 years ago
Q = mCp(ΔT).
Q = 1*23*(400-300),
Q = 2300.
Q = 1*23*(400-300),
Q = 2300.
(1)
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