Chemical Engineering - Chemical Engineering Basics - Discussion
Discussion Forum : Chemical Engineering Basics - Section 6 (Q.No. 2)
2.
In a counter flow heat exchanger, hot fluid enters at 170°C & leaves at 150°C, while the cold fluid enters at 50°C & leaves at 70°C. The arithmetic mean temperature difference in this case is __________ °C.
Discussion:
11 comments Page 1 of 2.
Ashok kumar said:
9 years ago
= (170 - 70) / (150 - 50),
ln (100 / 100) is equal to infinity.
ln (100 / 100) is equal to infinity.
Romil kikani said:
9 years ago
I think it is logarithmic mean, not an arithmetic mean.
Sk jha said:
8 years ago
@Ashok
I don't think so.
AMTD = (170+150)/2 - (70+50)/2,
= 320/2 - 120/2,
= 160 - 60 = 100 Ans.
I don't think so.
AMTD = (170+150)/2 - (70+50)/2,
= 320/2 - 120/2,
= 160 - 60 = 100 Ans.
Tejprakash said:
8 years ago
Yes, I agree with you @Ashok.
Raj Musale said:
6 years ago
The answer is 100° C.
Nilesh Singh said:
5 years ago
T1 = 170 - 150 = 20,
T2 = 50 - 70 = -20.
AM=20+(-20)/2= infinity.
T2 = 50 - 70 = -20.
AM=20+(-20)/2= infinity.
Neeraj kumar said:
4 years ago
LMTD= ΔT1/ln(ΔT1/ΔT2)
ΔT1=170-70 = 100.
ΔT2=150-50 = 50.
Then LMTD = 100/Ln(100/100),
= 100/0.
= ~ infinite.
Options D is the right answer.
ΔT1=170-70 = 100.
ΔT2=150-50 = 50.
Then LMTD = 100/Ln(100/100),
= 100/0.
= ~ infinite.
Options D is the right answer.
Nitesh ghidode said:
4 years ago
It's a log mean temperature difference.
Nitesh Ghidode said:
4 years ago
Answer should be 100 for AMTD and Infinite for LMTD.
TANMAY SHAH said:
3 years ago
Arithmetic Mean Temperature Difference is the average temperature of hot and cold fluids.
AMTD = ((HTs + HTe)/2) - ((CTs + CTe) /2)
Where HTs and HTe denote the start and end temperature of the Hot Stream. CTs and CTe indicates the start and end temperature of the Cool Stream.
So, here.
AMTD = ((170+150)/2) - ((50+70)/2).
AMTD = 100.
AMTD = ((HTs + HTe)/2) - ((CTs + CTe) /2)
Where HTs and HTe denote the start and end temperature of the Hot Stream. CTs and CTe indicates the start and end temperature of the Cool Stream.
So, here.
AMTD = ((170+150)/2) - ((50+70)/2).
AMTD = 100.
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